Ajout backups

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Louis Lacoste 2024-05-23 09:20:21 +02:00
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@ -381,6 +381,35 @@
\end{block} \end{block}
\end{frame} \end{frame}
\begin{frame}{Critère de sélection de modèle BIC-L}
\only<1>{\begin{block}{$iid\text{-}colBiSBM$}
\begin{itemize}
\item Pour les $\pi$s et $\rho$s:\\
$\text{pen}_{\pi}(Q_1) = (Q_1 - 1)\log(\sum_{m=1}^{M}n_{1}^{m})$\\
$\text{pen}_{\rho}(Q_2) = (Q_2 - 1)\log(\sum_{m=1}^{M}n_{2}^{m})$
\item Pour les $\alpha$s :
$\text{pen}_{\alpha}(Q_1, Q_2) = Q_1 \times Q_2 \log(N_M)$\\
avec $ N_M = \sum_{m = 1}^{M} n_{1}^{m} \times n_{2}^{m} $
\end{itemize}
\[ \text{BIC-L}(\bm{X},Q_1, Q_2) = \max_{\theta} \mathcal{J} (\mathcal{\hat{R}}, \bm{\theta})
- \frac{1}{2} [\text{pen}_{\pi}(Q_1) + \text{pen}_{\rho}(Q_2) + \text{pen}_{\alpha}(Q_1, Q_2)]\]
\end{block}}
\only<2>{\begin{block}{$\pi\rho\text{-}colBiSBM$}
\begin{itemize}
\item Les pénalités des supports :\\
$ \text{pen}_{S_1}(Q_1) = -2 \log p_{Q_1} (S_1) $\\
$\text{pen}_{S_2}(Q_2) = -2 \log p_{Q_2} (S_2) $
avec
$ \log p_{Q_1}(S_1) = - M \log(Q_1) - \sum_{m=1}^{M} \log {Q_1 \choose Q_1^{(m)}} $\\
$ \log p_{Q_2}(S_2) = - M \log(Q_2) - \sum_{m=1}^{M} \log {Q_2 \choose Q_2^{(m)}} $
\item Penalties for the $\rho$s and $\pi$s:\\
$ \text{pen}_{\pi}(Q_1, S_1) = \sum_{m=1}^{M} (Q_{1}^{(m)} - 1) \log n_{1}^{m} $\\
$ \text{pen}_{\rho}(Q_2, S_2) = \sum_{m=1}^{M} (Q_{2}^{(m)} - 1) \log n_{2}^{m} $
\item Penalties for the $\alpha$s:\\
$ \text{pen}_{\alpha}(Q_1, Q_2, S_1, S_2) = (\sum_{q=1}^{Q_1} \sum_{r=1}^{Q_2} \mathbb{1}_{(S_1)'S_2 > 0}) \log (N_M) $
\end{itemize}
\end{block}}
\end{frame}
\begin{frame} \begin{frame}
\frametitle{Sélection de modèle : choix de $(Q_1,Q_2)$ - Approche \frametitle{Sélection de modèle : choix de $(Q_1,Q_2)$ - Approche
@ -679,10 +708,22 @@
\section{Autres questions} \section{Autres questions}
\begin{frame}{\emph{Message passing} et \emph{Graph Convolutional Network}} \begin{frame}{\emph{Message passing} et \emph{Graph Convolutional Network}}
TODO Formule \begin{figure}[ht]
Fonction de perte possible \centering
\includegraphics[scale=0.5]{img/Message_passing.pdf}
\caption{Illustration du \emph{message passing}}
\label{fig:message-passing}
\end{figure}
\begin{block}{Formule des \emph{Graph Convolutional Network}}
\begin{itemize}
\item $H^{(\ell+1)} = \sigma (\tilde{D}^{-1/2} \tilde{A} \tilde{D}^{-1/2} H^{(\ell)} W^{(\ell)})$
\item $h^{(\ell+1)} = \sigma (\sum_{j\in\mathcal{N}(i)} \frac{1}{\sqrt{deg(i)deg(j)}} W^{(\ell)}x_j)$
\end{itemize}
\end{block}
% TODO Formule
% Fonction de perte possible
\end{frame} \end{frame}
\begin{frame}{Distance de Wasserstein} % \begin{frame}{Distance de Wasserstein}
TODO % TODO
\end{frame} % \end{frame}

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